Amines Chapter-Wise Test 2

Correct answer Carries: 4.

Wrong Answer Carries: -1.

The IUPAC name of \( \ce{CH3CH2CH2CH2NH2} \) is:

The compound has a four-carbon chain with an amine group on the first carbon, named butan-1-amine, as per the PDF’s nomenclature.

Butan-2-amine
Pentan-1-amine
Butan-1-amine
N-Methylpropanamine
3

The order of reactivity of amines with \( \ce{CH3COCl} \) is:

Reactivity decreases as substitution on nitrogen increases due to steric hindrance and lone pair availability: primary > secondary > tertiary, as per the PDF’s chemical properties.

Tertiary > Secondary > Primary
Secondary > Primary > Tertiary
Primary > Secondary > Tertiary
Primary > Tertiary > Secondary
3

Which amine would form the smallest alcohol when reacted with \( \ce{HNO2} \)?

Methylamine (\( \ce{CH3NH2} \)) reacts with \( \ce{HNO2} \) to form methanol (\( \ce{CH3OH} \)), the smallest alcohol, as per the PDF’s chemical properties.

\( \ce{CH3NH2} \)
\( \ce{CH3CH2NH2} \)
\( \ce{CH3CH2CH2NH2} \)
\( \ce{CH3CH2CH2CH2NH2} \)
1

Which of the following has the highest solubility in water?

Solubility depends on hydrogen bonding with water. \( \ce{CH3NH2} \) (primary amine) forms more hydrogen bonds than \( \ce{(CH3)2NH} \) (secondary) or \( \ce{(CH3)3N} \) (tertiary), and \( \ce{C6H5NH2} \) has lower solubility due to the hydrophobic benzene ring.

\( \ce{(CH3)2NH} \)
\( \ce{(CH3)3N} \)
\( \ce{C6H5NH2} \)
\( \ce{CH3NH2} \)
4

Which amine has the highest water solubility among the following?

Methylamine (\( \ce{CH3NH2} \)) has the smallest alkyl group, allowing maximum hydrogen bonding with water, as per the PDF’s physical properties.

\( \ce{CH3NH2} \)
\( \ce{CH3CH2CH2NH2} \)
\( \ce{(CH3CH2)2NH} \)
\( \ce{(CH3)3N} \)
1

Which amine can donate the most hydrogen bonds per molecule to water?

Primary amines like \( \ce{CH3CH2NH2} \) have two N-H bonds to donate and one lone pair to accept, allowing up to two hydrogen bonds donated, as per the PDF’s solubility.

\( \ce{CH3CH2NH2} \)
\( \ce{(CH3CH2)2NH} \)
\( \ce{(CH3CH2)3N} \)
\( \ce{(CH3)2NCH2CH3} \)
1

The product of the reaction \( \ce{CH3CH2CH2NO2} + \ce{Sn/HCl} \rightarrow \) is:

Reduction of nitropropane (\( \ce{CH3CH2CH2NO2} \)) with \( \ce{Sn/HCl} \) yields propan-1-amine (\( \ce{CH3CH2CH2NH2} \)), as per the PDF’s preparation methods.

\( \ce{CH3CH2CH2NH2} \)
\( \ce{CH3CH2NH2} \)
\( \ce{CH3CH2CH2OH} \)
\( \ce{CH3CH2NO} \)
1

A compound \( X \) on reduction with \( \ce{Sn/HCl} \) gives \( \ce{C6H5CH2NH2} \). \( X \) is:

Benzyl nitro compound (\( \ce{C6H5CH2NO2} \)) is reduced to benzylamine (\( \ce{C6H5CH2NH2} \)) with \( \ce{Sn/HCl} \), as per the PDF’s preparation methods.

\( \ce{C6H5NH2} \)
\( \ce{C6H5CH2NO2} \)
\( \ce{C6H5NO2} \)
\( \ce{C6H5CH2Cl} \)
2

The strongest base in aqueous solution among the following is:

Secondary amines like \( \ce{(CH3CH2)2NH} \) have higher basicity in water due to inductive and solvation effects, surpassing primary and tertiary amines, as per the PDF.

\( \ce{CH3CH2NH2} \)
\( \ce{(CH3CH2)2NH} \)
\( \ce{(CH3CH2)3N} \)
\( \ce{NH3} \)
2

The bond angle in trimethylamine is approximately:

Trimethylamine (\( \ce{(CH3)3N} \)) has a pyramidal shape due to \( sp^3 \) hybridization of nitrogen with a lone pair. The bond angle is less than 109.5° due to lone pair repulsion, approximately 108°.

108°
109.5°
120°
90°
1

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