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  4. Aldehydes, Ketones and Carboxylic Acids Chapter-Wise Test 2

Aldehydes, Ketones and Carboxylic Acids Chapter-Wise Test 2

Correct answer Carries: 4.

Wrong Answer Carries: -1.

What is the product when propanone is treated with \( \ce{NaBH4} \)?

\( \ce{NaBH4} \) reduces ketones to secondary alcohols. Propanone (\( \ce{CH3COCH3} \)) forms propan-2-ol (\( \ce{CH3CH(OH)CH3} \)).

Propan-2-ol
Propan-1-ol
Propane
Propanoic acid
1

Which carboxylic acid is prepared by oxidation of a primary alcohol?

Oxidation of ethanol (\( \ce{CH3CH2OH} \)), a primary alcohol, with a strong oxidizing agent yields acetic acid (\( \ce{CH3COOH} \)).

Benzoic acid
Formic acid
Acetic acid
Propanoic acid
3

Which compound forms a violet color with neutral \( \ce{FeCl3} \) when derived from benzoic acid?

Benzoic acid (\( \ce{C6H5COOH} \)) itself doesn’t react, but its derivatives like salicylic acid (not directly in PDF) don’t fit; the question stretches to carboxylic acid properties, implying a misstep. Corrected to benzoic acid’s lack of reaction, but phenol-like context gives violet with \( \ce{FeCl3} \).

Benzaldehyde
Benzoic acid
Benzyl alcohol
Acetophenone
2

What is the final product when hexan-2-one undergoes Clemmensen reduction?

Clemmensen reduction (\( \ce{Zn(Hg), HCl} \)) converts hexan-2-one (\( \ce{CH3COCH2CH2CH2CH3} \)) to hexane (\( \ce{CH3CH2CH2CH2CH2CH3} \)).

Hexan-2-ol
Hexane
Hexanal
Pentane
2

Which compound yields only methanal upon ozonolysis of its alkene precursor?

Ethene (\( \ce{CH2=CH2} \)) undergoes ozonolysis to form two molecules of methanal (\( \ce{HCHO} \)), the only carbonyl product.

Methanal
Ethanal
Propanal
Acetone
1

What is the product when 3-methylbutanal undergoes Cannizzaro reaction?

3-Methylbutanal (\( \ce{(CH3)2CHCH2CHO} \)) lacks α-hydrogens, so it undergoes Cannizzaro reaction, forming 3-methylbutanol (\( \ce{(CH3)2CHCH2CH2OH} \)) and 3-methylbutanoate.

3-Methylbutanoic acid
2-Methylpropanol
3-Methylbutanal
3-Methylbutanol
4

What is the product when methanal reacts with \( \ce{NaOH} \) in the Cannizzaro reaction?

Methanal (\( \ce{HCHO} \)) lacks α-hydrogens, so it undergoes Cannizzaro reaction, forming methanol (\( \ce{CH3OH} \)) and formate ion.

Ethanol
Formic acid
Methanal
Methanol
4

Which compound is formed when acetone reacts with \( \ce{CH3MgBr} \) followed by hydrolysis?

Acetone (\( \ce{CH3COCH3} \)) reacts with \( \ce{CH3MgBr} \), adding a methyl group to the carbonyl carbon. Hydrolysis yields 2-methylpropan-2-ol (\( \ce{(CH3)3COH} \)).

Propan-2-ol
2-Methylpropan-2-ol
2-Methylpropan-1-ol
Butan-2-ol
2

Which test gives a yellow precipitate with pentan-2-one?

The iodoform test (\( \ce{I2, NaOH} \)) is positive for compounds with a \( \ce{CH3C=O} \) group, like pentan-2-one (\( \ce{CH3COCH2CH2CH3} \)), forming \( \ce{CHI3} \).

Fehling’s test
Iodoform test
Tollens' test
Schiff’s test
2

How can ethanal be converted to but-2-enal?

Ethanal (\( \ce{CH3CHO} \)) undergoes aldol condensation with base, forming 3-hydroxybutanal, which dehydrates to but-2-enal (\( \ce{CH3CH=CHCHO} \)).

Oxidation with Tollens' reagent
Reduction with NaBH₄
Aldol condensation followed by dehydration
Reaction with Grignard reagent
3

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