Structure of Atom Chapter-Wise Test 5

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which quantum number determines the shape of an orbital?

The azimuthal quantum number \( l \) determines the shape of an orbital (e.g., s, p, d).

Principal quantum number (\( n \))
Magnetic quantum number (\( m_l \))
Azimuthal quantum number (\( l \))
Spin quantum number (\( m_s \))
3

How many orbitals in an atom can have the quantum numbers \( n = 4 \) and \( l = 3 \)?

For \( l = 3 \) (f subshell), number of orbitals = \( 2l + 1 = 2 \times 3 + 1 = 7 \).

5
3
7
9
3

Which transition in a hydrogen atom corresponds to the emission in the ultraviolet region?

UV region corresponds to the Lyman series (\( n_2 > 1 \) to \( n_1 = 1 \)). \( n = 2 \) to \( n = 1 \) is in this series.

\( n = 3 \) to \( n = 2 \)
\( n = 2 \) to \( n = 1 \)
\( n = 4 \) to \( n = 3 \)
\( n = 5 \) to \( n = 2 \)
2

An atom has 20 protons, 22 neutrons, and 18 electrons. What is its mass number and charge?

Mass number = protons + neutrons = 20 + 22 = 42. Charge = protons - electrons = 20 - 18 = +2.

\( 40, +2 \)
\( 42, -2 \)
\( 42, +2 \)
\( 40, -2 \)
3

An atom has 32 protons, 38 neutrons, and 30 electrons. What is its mass number and charge?

Mass number = 32 + 38 = 70. Charge = 32 - 30 = +2.

\( 70, -2 \)
\( 68, +2 \)
\( 70, +2 \)
\( 68, -2 \)
3

An electron in \( \text{Be}^{3+} \) has an angular momentum of \( 6.33 \times 10^{-34} \, \text{J s} \). What is its energy? (\( h = 6.626 \times 10^{-34} \, \text{J s} \), \( E_1 \) for H = \( -2.18 \times 10^{-18} \, \text{J} \))

\( n = \frac{L \cdot 2\pi}{h} = \frac{6.33 \times 10^{-34} \times 2 \times 3.14}{6.626 \times 10^{-34}} = 6 \). For \( \text{Be}^{3+} \) (Z = 4), \( E_6 = -16 \times 2.18 \times 10^{-18} / 36 = -9.6778 \times 10^{-19} \, \text{J} \).

\( -2.42 \times 10^{-18} \, \text{J} \)
\( -3.871 \times 10^{-18} \, \text{J} \)
\( -1.089 \times 10^{-18} \, \text{J} \)
\( -9.6778 \times 10^{-19} \, \text{J} \)
4

The velocity of an electron in the first orbit of a hydrogen atom is \( 2.19 \times 10^6 \, \text{m s}^{-1} \). What is its velocity in the third orbit?

Velocity \( v_n = \frac{v_1}{n} \). For \( n = 3 \), \( v_3 = \frac{2.19 \times 10^6}{3} = 7.3 \times 10^5 \, \text{m s}^{-1} \).

\( 7.3 \times 10^5 \, \text{m s}^{-1} \)
\( 2.19 \times 10^6 \, \text{m s}^{-1} \)
\( 1.46 \times 10^6 \, \text{m s}^{-1} \)
\( 6.57 \times 10^6 \, \text{m s}^{-1} \)
1

The energy of an electron in the second orbit of \( \text{He}^+ \) is \( -13.6 \, \text{eV} \). What is the ionization energy from the fourth orbit? (\( 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \))

For \( \text{He}^+ \) (Z = 2), \( E_n = -54.4 / n^2 \). \( E_4 = -54.4 / 16 = -3.4 \, \text{eV} \). Ionization energy = \( 0 - (-3.4) = 3.4 \, \text{eV} \).

\( 13.6 \, \text{eV} \)
\( 3.4 \, \text{eV} \)
\( 6.8 \, \text{eV} \)
\( 54.4 \, \text{eV} \)
2

The angular momentum of an electron in the fourth orbit of \( \text{He}^+ \) is \( 4.22 \times 10^{-34} \, \text{J s} \). What is the frequency of the photon emitted when it falls to the second orbit? (\( h = 6.626 \times 10^{-34} \, \text{J s} \), \( E_1 \) for H = \( -2.18 \times 10^{-18} \, \text{J} \))

\( n = \frac{L \cdot 2\pi}{h} = \frac{4.22 \times 10^{-34} \times 2 \times 3.14}{6.626 \times 10^{-34}} = 4 \). For \( \text{He}^+ \) (Z = 2), \( E_2 = -4 \times 2.18 \times 10^{-18} / 4 = -2.18 \times 10^{-18} \, \text{J} \), \( E_4 = -4 \times 2.18 \times 10^{-18} / 16 = -5.45 \times 10^{-19} \, \text{J} \). \( \Delta E = 1.635 \times 10^{-18} \, \text{J} \). \( v = \frac{\Delta E}{h} = 2.467 \times 10^{15} \, \text{Hz} \).

\( 2.467 \times 10^{15} \, \text{Hz} \)
\( 3.291 \times 10^{15} \, \text{Hz} \)
\( 1.645 \times 10^{15} \, \text{Hz} \)
\( 4.935 \times 10^{15} \, \text{Hz} \)
1

An atom has 26 protons, 30 neutrons, and 24 electrons. What is its mass number and charge?

Mass number = 26 + 30 = 56. Charge = 26 - 24 = +2.

\( 56, -2 \)
\( 54, +2 \)
\( 56, +2 \)
\( 54, -2 \)
3

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