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  4. Organic Chemistry: Some Basic Principles and Techniques Chapter-Wise Test 2

Organic Chemistry: Some Basic Principles and Techniques Chapter-Wise Test 2

Correct answer Carries: 4.

Wrong Answer Carries: -1.

A compound with 10 \( \sigma \) bonds and 2 \( \pi \) bonds has the formula \( \ce{C5H6} \). Which carbon has a bond angle of 180°?

\( \ce{CH2=CHC#CH} \) fits \( \ce{C5H6} \) with 10 \( \sigma \) (6 C-H, 2 C-C, 1 from C=C, 1 from C≡C) and 2 \( \pi \) (1 C=C, 1 C≡C). The fourth carbon (\( \ce{C#} \)) is \( sp \), with a 180° angle.

First carbon
Second carbon
Fourth carbon
Third carbon
3

What is the IUPAC name of \( \ce{CH3CH(OH)CH2CH3} \)?

The compound \( \ce{CH3CH(OH)CH2CH3} \) has 4 carbons, with an -OH group on the second carbon. The longest chain is butane, and the -OH makes it butan-2-ol.

Butan-2-ol
Butan-1-ol
2-Methylpropan-1-ol
Propan-2-ol
1

In the estimation of sulphur, 0.15 g of an organic compound gave 0.505 g of \( \ce{BaSO4} \). What is the percentage of sulphur?

Molar mass of \( \ce{BaSO4} = 233 \) g/mol, S = 32 g/mol. Mass of S = \( \frac{32}{233} \times 0.505 = 0.069 \) g. Percentage = \( \frac{0.069}{0.15} \times 100 = 46\% \).

40%
44%
46%
50%
3

A mixture of two liquids (b.p. 80°C and 85°C) shows an \( R_f \) difference of 0.3 in paper chromatography. Which technique is most efficient for large-scale separation?

Close boiling points (5°C difference) require fractional distillation for large-scale separation, as chromatography is better for analytical purposes.

Simple distillation
Paper chromatography
Fractional distillation
Differential extraction
3

Which method cannot be used to estimate nitrogen in compounds containing nitro groups?

Kjeldahl’s method fails for nitro compounds (\( \ce{-NO2} \)) as nitrogen is not easily converted to \( \ce{NH3} \); Dumas method is preferred.

Dumas method
Carius method
Lassaigne’s test
Kjeldahl’s method
4

Which of the following is a free radical?

A free radical has an unpaired electron. \( \ce{CH3.} \) is formed by homolytic cleavage and has an unpaired electron on carbon.

\( \ce{CH3.} \)
\( \ce{CH3+} \)
\( \ce{CH3^-} \)
\( \ce{CH3CH2+} \)
1

Which functional group is present in \( \ce{CH3CH2CHO} \)?

\( \ce{CH3CH2CHO} \) (propanal) contains the \( \ce{-CHO} \) group, characteristic of aldehydes.

Ketone
Aldehyde
Alcohol
Carboxylic acid
2

Which purification method is most suitable for separating a mixture of two liquids with boiling points of 98°C and 102°C, both miscible in water?

Close boiling points (4°C difference) require fractional distillation for effective separation, as simple distillation is insufficient and solubility doesn’t aid here.

Simple distillation
Differential extraction
Sublimation
Fractional distillation
4

A compound \( \ce{C5H10O} \) shows no reaction with sodium fusion followed by silver nitrate test. Which functional group is most likely present?

No reaction with Lassaigne’s test (sodium fusion + \( \ce{AgNO3} \)) indicates no halogens. \( \ce{CH3CH2COCH2CH3} \) (pentan-3-one) is a ketone, consistent with \( \ce{C5H10O} \), and lacks halogens.

Aldehyde
Ketone
Ether
Alcohol
2

Which method is used to estimate nitrogen in an organic compound by converting it to ammonium sulphate?

Kjeldahl’s method involves heating the compound with \( \ce{H2SO4} \) to form \( \ce{(NH4)2SO4} \), followed by ammonia liberation and titration.

Dumas method
Kjeldahl’s method
Carius method
Lassaigne’s test
2

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