1. Home
    2. >
  2. Neet Chemistry Class 11 Mock Test Papers
    3. >
  3. Chemistry Chapter Wise Test Papers
    4. >
  4. Chemical Bonding and Molecular Structure Chapter-Wise Test 3

Chemical Bonding and Molecular Structure Chapter-Wise Test 3

Correct answer Carries: 4.

Wrong Answer Carries: -1.

Which molecule contains a coordinate bond where nitrogen donates a lone pair to boron?

In \( \ce{H3NBF3} \), nitrogen in \( \ce{NH3} \) donates a lone pair to boron in \( \ce{BF3} \), forming a coordinate bond.

\( \ce{H3NBF3} \)
\( \ce{NH3} \)
\( \ce{BF3} \)
\( \ce{CH4} \)
1

The bond order of \( \ce{O2^2-} \) ion, based on molecular orbital theory, is:

For \( \ce{O2^2-} \) (18 electrons): \( (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^2 (\pi^* 2p_y)^2 \). Bonding = 10, antibonding = 8. Bond order = \( \frac{10 - 8}{2} = 1 \).

1
1.5
2
2.5
1

The number of sigma bonds in \( \ce{C2H6} \) molecule is:

In \( \ce{C2H6} \) (ethane), there is one \( \ce{C-C} \) sigma bond and six \( \ce{C-H} \) sigma bonds, totaling 7.

6
7
8
5
2

The total number of sigma and pi bonds in \( \ce{C5H8} \) (1,3-pentadiene, \( \ce{CH2=CH-CH=CH-CH3} \)) is:

In \( \ce{CH2=CH-CH=CH-CH3} \): 2 double bonds (2 sigma, 2 pi), 2 \( \ce{C-C} \) sigma, 8 \( \ce{C-H} \) sigma. Total = 12 sigma + 2 pi = 14 bonds.

13
14
15
12
2

Which of the following species has a bond order of 2?

For \( \ce{O2} \): \( (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1 \). Bonding electrons = 10, antibonding = 6. Bond order = \( \frac{10 - 6}{2} = 2 \).

\( \ce{N2} \)
\( \ce{O2} \)
\( \ce{F2} \)
\( \ce{He2} \)
2

Which molecule has a bond order of 3 and is diamagnetic?

For \( \ce{N2} \): \( (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^2 \). Bonding = 10, antibonding = 4. Bond order = \( \frac{10 - 4}{2} = 3 \), with all electrons paired (diamagnetic).

\( \ce{O2} \)
\( \ce{B2} \)
\( \ce{N2} \)
\( \ce{NO} \)
3

Which molecule has a bent shape due to the presence of lone pairs?

In \( \ce{H2O} \), oxygen has two lone pairs and two bonding pairs, resulting in a bent shape with a bond angle of 104.5°.

\( \ce{CO2} \)
\( \ce{H2O} \)
\( \ce{BeCl2} \)
\( \ce{BF3} \)
2

The number of pi bonds in \( \ce{C4H6} \) (butadiene, \( \ce{CH2=CH-CH=CH2} \)) is:

In \( \ce{CH2=CH-CH=CH2} \), there are 2 double bonds (each with 1 pi bond), totaling 2 pi bonds, plus 9 sigma bonds (4 \( \ce{C-H} \), 3 \( \ce{C-C} \), 2 from double bonds).

1
3
4
2
4

Which molecule contains a triple bond and has a bond length of approximately 120 pm?

In \( \ce{C2H2} \) (ethyne), the \( \ce{C#C} \) triple bond has a bond length of ~120 pm, shorter than typical double or single bonds.

\( \ce{N2} \)
\( \ce{C2H2} \)
\( \ce{CO2} \)
\( \ce{SO2} \)
2

Which molecule exhibits hydrogen bonding and has a bond angle of approximately 104.5°?

In \( \ce{H2O} \), oxygen is \( sp^3 \) hybridized with 4 electron pairs (2 bonding, 2 lone), resulting in a bent shape with a 104.5° angle and strong hydrogen bonding.

\( \ce{NH3} \)
\( \ce{H2O} \)
\( \ce{HF} \)
\( \ce{CH4} \)
2

Performance Summary

Score:

Category Details
Total Attempts:
Total Skipped:
Total Wrong Answers:
Total Correct Answers:
Time Taken:
Average Time Taken per Question:
Accuracy:
0
error: Content is protected !!